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Math Help - Differentiation

  1. #1
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    Differentiation

    I am unsure if I have done the following correctly

    The question: Differentiate y=\sqrt{x^2 + \cosh^4x}

    I get my answer as \frac{dy}{dx} = \frac{1}{2(x^2 + \cosh^4)^2}

    Thanks for any help or suggestions, they are greatly appreciated.

    Beard
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  2. #2
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    Here, the Chain Rule may be used along with the Power Rule:

    \frac{dy}{dx}=\frac{d}{dx}\sqrt{x^2+\cosh^4 x}=\frac{1}{2\sqrt{x^2+\cosh^4 x}}\frac{d}{dx}(x^2+\cosh^4 x).
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  3. #3
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    Quote Originally Posted by Scott H View Post
    Here, the Chain Rule may be used along with the Power Rule:

    \frac{dy}{dx}=\frac{d}{dx}\sqrt{x^2+\cosh^4 x}=\frac{1}{2\sqrt{x^2+\cosh^4 x}}\frac{d}{dx}(x^2+\cosh^4 x).
    So is this saying that I was right?
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  4. #4
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    Quote Originally Posted by Scott H View Post
    Here, the Chain Rule may be used along with the Power Rule:

    \frac{dy}{dx}=\frac{d}{dx}\sqrt{x^2+\cosh^4 x}=\frac{1}{2\sqrt{x^2+\cosh^4 x}}\frac{d}{dx}(x^2+\cosh^4 x).
    I have tried redo this to see if i could simplify it in a better way but I am unsure about the answer I got

    \frac{1}{8(x^2 + 2\sinh^{3}(x) + 2\sinh^{6}h(x))}

    Does anyone know if this is the right conclusion
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