Find the area of a region bounded by the graph f(x)=27-x^3 and vertical lines x=3 and x=1. Thank you.
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Originally Posted by ihatemath Find the area of a region bounded by the graph f(x)=27-x^3 and vertical lines x=3 and x=1. Thank you. I take it it's also bounded by the horizontal axis as well... You need to evaluate $\displaystyle \int_1^3{27 - x^3\,dx}$.
Ok, how would I do that?
$\displaystyle \int_1^3{27 - x^3\,dx} = \left[27x - \frac{1}{4}x^4\right]_1^3$ $\displaystyle = \left[27(3) - \frac{1}{4}(3)^4\right] - \left[27(1) - \frac{1}{4}(1)^4\right]$. Can you go from there?
Ohhh.. ok.. I see what I did wrong.. Thank You SOO much!
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