# Thread: Areas in the Plane (Calculus)

1. ## Areas in the Plane (Calculus)

I can't figure out why I keep on getting the wrong answer for this problem. I would appreciate any help.

Find the area of the "triangular" region in the first quadrant bounded on the left by the y-axis and on the right by the curves y = sinx and y = cosx

2. Look at hand drawn picture below.
They intersect at 0 and $\pi/4$.
The top curve is cosine and bottom is sine:
$\int_0^{\pi/4} (\cos x-\sin x) dx$