Originally Posted by

**mark** hi, my question is: find and equation of the tangent to the following curve at the point where x = 0

$\displaystyle y = 3x^4 + 5x - 2$

first i differentiated so i could find the gradient: $\displaystyle \frac{dy}{dx} = 12x^3 + 5$ then subbing x = 0 into the equation you get 5 for the gradient.

using x = 0 you can also see that from the original equation y = -2

then using the equation formula $\displaystyle y - y1 = m(x - x1)$ i got $\displaystyle y + 2 = 5(x - 0) \implies y = - 2$ so the equation looks to me like it should be y = -2

the answer in the back gives $\displaystyle y = 5x - 2$ for the equation

can someone show me what i'm doing wrong please,

thankyou

ps what do you have to type into latex to get the 1's in $\displaystyle y - y1 = m(x - x1)$ to appear small and at the bottom of the x and y if you know what i mean? like the same size as "to the power of" but at the bottom