Find constants a and b in the function f(x)=axe^(bx) such that f(1/3)=1 and the function has a local maximum at x=1/3. Thanks!
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Originally Posted by iheartthemusic29 Find constants a and b in the function f(x)=axe^(bx) such that f(1/3)=1 and the function has a local maximum at x=1/3. Thanks! Solve the following simultaneously: $\displaystyle 1 = \frac{a}{3} e^{b/3}$ .... (1) $\displaystyle f'(1/3) = 0 \Rightarrow a e^{b/3} + \frac{ab}{3} e^{b/3} = 0$ .... (2)
I figured it out. a=3e and b=-3 Thanks!
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