Simplify the expression tanh(lnt).
I thought the answer was (t^2-1)/(t^2+1), but that's not correct, and I can't figure out why. Can somebody give me a hand? Thanks!
Simplify the expression tanh(lnt).
I thought the answer was (t^2-1)/(t^2+1), but that's not correct, and I can't figure out why. Can somebody give me a hand? Thanks!
Simplify the expression tanh(lnt).
I thought the answer was (t^2-1)/(t^2+1), but that's not correct, and I can't figure out why. Can somebody give me a hand? Thanks!
Well, it is correct: $\displaystyle \tanh x = \frac{e^x-e^{-x}}{e^x+e^{-x}}$ , and aplying on $\displaystyle \ln x$ we get what you got.