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Math Help - Hyperbolic Tangent

  1. #1
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    Hyperbolic Tangent

    Simplify the expression tanh(lnt).
    I thought the answer was (t^2-1)/(t^2+1), but that's not correct, and I can't figure out why. Can somebody give me a hand? Thanks!
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  2. #2
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    Quote Originally Posted by iheartthemusic29 View Post
    Simplify the expression tanh(lnt).
    I thought the answer was (t^2-1)/(t^2+1), but that's not correct, and I can't figure out why. Can somebody give me a hand? Thanks!
    .
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  3. #3
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    Quote Originally Posted by iheartthemusic29 View Post
    Simplify the expression tanh(lnt).
    I thought the answer was (t^2-1)/(t^2+1), but that's not correct, and I can't figure out why. Can somebody give me a hand? Thanks!

    Well, it is correct: \tanh x = \frac{e^x-e^{-x}}{e^x+e^{-x}} , and aplying on \ln x we get what you got.

    Who says that's not the correct answer?

    Tonio
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