Find dydx in terms of x and y if arcsin((x^5)(y))=(x)(y^5) I tried to do this problem, and I got (y^5((1-(x^5y)^2))^(1/2)-(5yx^4))/(x^5-5xy^4(((1-x^5y)^2))^(1/2)), which is incorrect. Help, please???
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Originally Posted by iheartthemusic29 Find dydx in terms of x and y if arcsin((x^5)(y))=(x)(y^5) I tried to do this problem, and I got (y^5((1-(x^5y)^2))^(1/2)-(5yx^4))/(x^5-5xy^4(((1-x^5y)^2))^(1/2)), which is incorrect. Help, please??? I supose you mean to find dy/dx in...etc. $\displaystyle Arcsin\, (x^5y)=xy^5 \Longrightarrow \frac{5x^4y}{\sqrt{1-x^{10}y^2}}\,dx+\frac{x^5}{\sqrt{1-x^{10}y^2}}\,dy=y^5\,dx+5xy^4\,dy$ I bet you'll be able to continue from here. Tonio
Yeah, I got it. I actually had the right answer. It was an online assignment, and I put one parenthesis in the wrong spot when I was entering it, thus changing the entire answer. Thanks!
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