Evaluate: $\displaystyle \int_{\sqrt{2}}^{2} \dfrac{dx}{x\sqrt{x^{2}-1}}$

$\displaystyle \dfrac{1}{x\sqrt{x^{2}-1}}dx $ is the same as $\displaystyle arcsec(x) $

im not able to evaluate it from $\displaystyle \sqrt{2}$ to $\displaystyle 2$

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- Feb 4th 2007, 11:07 AMvietintergration with inverse trig
Evaluate: $\displaystyle \int_{\sqrt{2}}^{2} \dfrac{dx}{x\sqrt{x^{2}-1}}$

$\displaystyle \dfrac{1}{x\sqrt{x^{2}-1}}dx $ is the same as $\displaystyle arcsec(x) $

im not able to evaluate it from $\displaystyle \sqrt{2}$ to $\displaystyle 2$ - Feb 4th 2007, 11:27 AMticbol
- Feb 4th 2007, 12:01 PMThePerfectHacker
- Feb 4th 2007, 09:58 PMticbol