Hey everyone, I'm looking for help on how to solve this limit problem.
This is the information provided, sorry about the way I wrote it out.
h is continuous except at x=-1
lim x ->infinity of h(x)= infinity
lim x-> -1 of H(x)= 1/2
Find the value of lim x->0 of (3h(x)+f(x)-2g(x))
I've tried factoring out f(x) and using it in lim x->-1 of h(x)=(f(x))/(g(x)), but I keep arriving with 0 being the numerator, which can't be right since the limit's supposed to be 1/2. Any and all help would be appreciated, thanks.