# College Question (Simpsons Rule)

• Feb 4th 2007, 05:41 AM
zak_killcity14@hotmail.co
College Question (Simpsons Rule)
A plot of land is bound on two sides by straight roads at right angles to each other. The other boundary is irregular and the lengths of perpendicular offsets from one road to the irregular boundary are:14, 16, 15, 15, 14, 14, 13, 12, 10, 12, 12, 13, 12, 10, 8, 7, 7, 6, 6, meters. Calculate by using a suitable method the area of the plot of land (Simpsons Rule):confused:
• Feb 4th 2007, 07:47 AM
CaptainBlack
Quote:

Originally Posted by zak_killcity14@hotmail.co
A plot of land is bound on two sides by straight roads at right angles to each other. The other boundary is irregular and the lengths of perpendicular offsets from one road to the irregular boundary are:14, 16, 15, 15, 14, 14, 13, 12, 10, 12, 12, 13, 12, 10, 8, 7, 7, 6, 6, meters. Calculate by using a suitable method the area of the plot of land (Simpsons Rule):confused:

This is asking you to use Simpson's rule to calculate the area between the
axes and a curve which passes through the points (0,14), (h,16), (2h,15), ..., (18h,6).

This is:

A=(h/3)[14+4x16+2x15+4x15+ ... +4x6+6]=(h/3)x622,

but as it seems to be keeping the value of h to itself there does not seem to be much more that can be done.

RonL
• Feb 4th 2007, 08:20 AM
zak_killcity14@hotmail.co
The Lecturer at college!!
The Lecturer at college said it is 6 meters i think
• Feb 4th 2007, 08:31 AM
CaptainBlack
Quote:

Originally Posted by zak_killcity14@hotmail.co
The Lecturer at college said it is 6 meters i think

Then:

(h/3)x622=1244 m^2

(assuming all data is in metres).

RonL
• Feb 5th 2007, 06:30 AM
zak_killcity14@hotmail.co
Cheers!!!
Cheers that is really helpful thanks again:) :D