College Question (Simpsons Rule)

A plot of land is bound on two sides by straight roads at right angles to each other. The other boundary is irregular and the lengths of perpendicular offsets from one road to the irregular boundary are:14, 16, 15, 15, 14, 14, 13, 12, 10, 12, 12, 13, 12, 10, 8, 7, 7, 6, 6, meters. Calculate by using a suitable method the area of the plot of land (Simpsons Rule):confused:

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Originally Posted by zak_killcity14@hotmail.co

A plot of land is bound on two sides by straight roads at right angles to each other. The other boundary is irregular and the lengths of perpendicular offsets from one road to the irregular boundary are:14, 16, 15, 15, 14, 14, 13, 12, 10, 12, 12, 13, 12, 10, 8, 7, 7, 6, 6, meters. Calculate by using a suitable method the area of the plot of land (Simpsons Rule):confused:

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This is asking you to use Simpson's rule to calculate the area between the
axes and a curve which passes through the points (0,14), (h,16), (2h,15), ..., (18h,6).

This is:

A=(h/3)[14+4x16+2x15+4x15+ ... +4x6+6]=(h/3)x622,

but as it seems to be keeping the value of h to itself there does not seem to be much more that can be done.

RonL

The Lecturer at college said it is 6 meters i think

Quote:

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Originally Posted by zak_killcity14@hotmail.co

The Lecturer at college said it is 6 meters i think

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Then:

(h/3)x622=1244 m^2

(assuming all data is in metres).

RonL

Cheers that is really helpful thanks again:) :D