Use the equations and relations given below to answer the following questions.

given

$\displaystyle f(pi/6) = 10$

$\displaystyle f'(pi/6) = -4$

$\displaystyle h(x) = (-sin(x)/f(x))$

what is $\displaystyle h'(pi/6) = ?$

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- Oct 28th 2009, 01:25 PMbreakderivatives with trigonometric functions
Use the equations and relations given below to answer the following questions.

given

$\displaystyle f(pi/6) = 10$

$\displaystyle f'(pi/6) = -4$

$\displaystyle h(x) = (-sin(x)/f(x))$

what is $\displaystyle h'(pi/6) = ?$ - Oct 28th 2009, 01:40 PMbreak
never mind, i just had to use the quotient rule, and find out the derivative of -sin(x) is -cos(x).