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Math Help - slant asymptotes

  1. #1
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    slant asymptotes

    Hey everybody,

    I learned a while back how to do slant asymptotes with polynomials, but I'm having trouble with finding the slant asymptote for:

    y = (e^x) - x

    ahh I feel so silly. Please help!
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  2. #2
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    Quote Originally Posted by DarthPipsqueak View Post
    Hey everybody,

    I learned a while back how to do slant asymptotes with polynomials, but I'm having trouble with finding the slant asymptote for:

    y = (e^x) - x

    ahh I feel so silly. Please help!
    Determine the limits of y if x is approaching \infty or -\infty:

    \lim_{x \to \infty}(e^x - x) = \infty that means there isn't any calculable limit.

    Since \lim_{x \to -\infty}(e^x)=0

    \lim_{x \to -\infty}(e^x - x) = -x That means the graph of the function approaches the line y = -x if x approaches -\infty

    and that is your slanted asymptote.
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  3. #3
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    Ah! I get it. Thanks so much! Appreciate the help
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