# Math Help - slant asymptotes

1. ## slant asymptotes

Hey everybody,

I learned a while back how to do slant asymptotes with polynomials, but I'm having trouble with finding the slant asymptote for:

y = (e^x) - x

2. Originally Posted by DarthPipsqueak
Hey everybody,

I learned a while back how to do slant asymptotes with polynomials, but I'm having trouble with finding the slant asymptote for:

y = (e^x) - x

Determine the limits of y if x is approaching $\infty$ or $-\infty$:
$\lim_{x \to \infty}(e^x - x) = \infty$ that means there isn't any calculable limit.
Since $\lim_{x \to -\infty}(e^x)=0$
$\lim_{x \to -\infty}(e^x - x) = -x$ That means the graph of the function approaches the line y = -x if x approaches $-\infty$