i have to find y' and y" using implicit differentiation
2x^3 - y^2 = 8
what i did was
d2x^3/dx - dy^2/dx = d8/dx
d2x^3/dx = 6x^2
dy^2/dx = 2y*y'
d8/dx = 0
6x^2 - 2yy' = 0
-6x^2=-2yy'
y'=6x^2/2y
= 3x^2 / y
but i don't know how to find 2nd derivative from here
how do i do it?