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Math Help - Help! Calculus Proof

  1. #1
    Newbie Sterwine's Avatar
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    Help! Calculus Proof

    Suppose delta > 0

    Prove that there exists a positive integer n such that

    0 < 1/(4n+1)pi/2 < delta

    and sin( (4n+1)pi)/2) = 1

    How do you do this?
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  2. #2
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    Quote Originally Posted by Sterwine View Post
    Suppose delta > 0
    Prove that there exists a positive integer n such that
    0 < 1/(4n+1)pi/2 < delta
    and sin( (4n+1)pi)/2) = 1
    It is very hard to read you post. I assume that it is \frac{1}{\frac{(4n+1)\pi}{2}}

    Do you understand that the sequence \left(\frac{2}{(4n+1)\pi}\right)\to 0?
    Then if \delta >0 that almost all of the terms of that sequence are less than \delta.
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  3. #3
    Newbie Sterwine's Avatar
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    I think the denominator is (4n+1) times Pi/2
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  4. #4
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    Quote Originally Posted by Sterwine View Post
    I think the denominator is (4n+1) times Pi/2
    You do understand that (4n+1)\cdot \frac{\pi}{2}=\frac{(4n+1)\pi}{2}?
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  5. #5
    Newbie Sterwine's Avatar
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    yes, yes I do
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