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Thread: Chain Rule Application

  1. October 27th 2009, 12:08 AM #1
    VitaX
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    Chain Rule Application

    Find the derivative of Sec^2(x+2)^3

    y' = 2Sec(x+2)^3(Sec(x+2)^3)(tan(x+2)^3)3(x+2)^2(1)

    6Sec(x+2)^3(Sec(x+2)^3)(tan(x+2)^3)(x+2)^2

    My question is when you multiply Sec(x+2)^3 and Sec(x+2)^3 would your answer be Sec^2(x+2)^3 or Sec(x+2)^6
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  2. October 27th 2009, 12:14 AM #2
    ramiee2010
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    Quote Originally Posted by VitaX View Post
    My question is when you multiply Sec(x+2)^3 and Sec(x+2)^3 would your answer be Sec^2(x+2)^3 or Sec(x+2)^6
    \sec(x+2)^3 \cdot \sec(x+2)^3=\{\sec(x+2)^3 \} ^2=Sec^2(x+2)^3
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  3. October 27th 2009, 12:15 AM #3
    VitaX
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    Quote Originally Posted by ramiee2010 View Post
    \sec(x+2)^3 \cdot \sec(x+2)^3=\{\sec(x+2)^3 \} ^2=Sec^2(x+2)^3
    I thought so. So the final answer is

    6 Sec^2(x+2)^3(tan(x+2)^3)(x+2)^2
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