f(x) = 18x + 15x^2 -4x^3 on the interval [-3,4]
A) f(-3) =
f(4) =
B) find the critical points of f(x) state x and y show your work
C) State the absolute maximum and absolute minimum values of the function on the interval [-3,4]
how do i get the critical points iv found the derivative to be 18+30x-12x^2 now what do i do?
Critical points are points at which the gradient of the function is zero. The gradient of a function f(x) is described by its derivative f'(x), so you're looking for the points at which f'(x) = 0.
So set f'(x) = 0, and solve for x. Once you have the values of x that solve this equation, plug them back into the original equation, f(x), to find the corresponding y values.