The question asks to find the point closest to the origin of the straight line perpendicular to a surface equation previously given. I found the equation for the normal line, but I am not sure how to find the point on the line closest to the origin. Can anyone tell me how to do this? Thanks in advance.

Here is the equation of the line...

$\displaystyle \frac{x-1}{6}=\frac{y-2}{3}=\frac{z-3}{2}$