Thread: about sequences 1

Hello,

Show that

Thanks in advance.

Originally Posted by Biscaim

Hello,

Show that

Thanks in advance.

It looks to me like you'll need to develop this expression as a series. See - Wolfram|Alpha

Originally Posted by Biscaim

Hello,

Show that

Thanks in advance.

. By definition of e, the numerator approaches 1 - 1/e * e = 0, so maybe applying L'Hopital's rule will be successful (I haven't tried it).