Hello, Show that Thanks in advance.
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Originally Posted by Biscaim Hello, Show that Thanks in advance. It looks to me like you'll need to develop this expression as a series. See - Wolfram|Alpha
Originally Posted by Biscaim Hello, Show that Thanks in advance. . By definition of e, the numerator approaches 1 - 1/e * e = 0, so maybe applying L'Hopital's rule will be successful (I haven't tried it).
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