A rocket lifts off the surface of Earth with a constant acceleration of 20 m/sec^2.
How fast will the rocket be going one minute later?
Can someone at least point me in the right direction? Thanks!
In a sense, you can solve the differential equation $\displaystyle \frac{\,dv}{\,dt}=20$, with initial condition $\displaystyle v\!\left(0\right)=0$.
In the end, its going to turn out to be $\displaystyle 20\frac{\text{m}}{\text{s}^2}\cdot 60\text{s}=1200\frac{\text{m}}{\text{s}}$