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Math Help - finding the integral

  1. #1
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    finding the integral

    \int {\frac{{{{(x - 2)}^2}{{\tan }^{ - 1}}(2x) - 12{x^3} - 3x}}<br />
{{(4{x^2} + 1){{(x - 2)}^2}}}} <br />

    can i cancel a {(x - 2)^2}<br />
?
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  2. #2
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    Quote Originally Posted by genlovesmusic09 View Post
    \int {\frac{{{{(x - 2)}^2}{{\tan }^{ - 1}}(2x) - 12{x^3} - 3x}}<br />
{{(4{x^2} + 1){{(x - 2)}^2}}}} <br />

    can i cancel a {(x - 2)^2}<br />
?
    you know better than that ...
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