Math Help - finding the integral

1. finding the integral

$\int {\frac{{{{(x - 2)}^2}{{\tan }^{ - 1}}(2x) - 12{x^3} - 3x}}
{{(4{x^2} + 1){{(x - 2)}^2}}}}
$

can i cancel a ${(x - 2)^2}
$
?

2. Originally Posted by genlovesmusic09
$\int {\frac{{{{(x - 2)}^2}{{\tan }^{ - 1}}(2x) - 12{x^3} - 3x}}
{{(4{x^2} + 1){{(x - 2)}^2}}}}
$

can i cancel a ${(x - 2)^2}
$
?
you know better than that ...