$\displaystyle f(x) = {7^{\sec (\theta )}}\ln 7 $ evaluated at $\displaystyle \theta = 0 $ not sure where to begin
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Originally Posted by genlovesmusic09 $\displaystyle f(x) = {7^{\sec (\theta )}}\ln 7 $ evaluated at $\displaystyle \theta = 0 $ not sure where to begin are you talking about f(0) or f'(0) ?
the derivative sorry i forgot to put that
i know that ln7 is just a constant and so you bring it down 7^secx*ln(secx)*ln7 but do i need to take the derivative of secx?
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