Find the limit. (If you need to use - or , enter -INFINITY or INFINITY.)
I would explain what ive done in more detail, but i know im missing something due to x approaching neg. infinity, but i did multiply the above funct. by its conjugate to get (x-1)/(x-square root of x^2+4x). How would i go about this? Thank you. -Evan
Ok here is what i have...
sqroot(t^2-4t)-t * sqroot(t^2-4t)+t
1 * sqroot(t^2-4t)+t
consolidate like terms then divide by t....
how can i properly solve for the denominator with the sqroot involved? I have something on paper that gets me sqroot(t-4)+1 which is most likely wrong. Thanks.
I see. How would i properly divide t by the denominator? I know this is easy, but my algebra is off. I know dividing by t in the sqroot wont really work unless t itself is within a square root, so t= sqroot(t^2), am i right? If thats so, then i can see sqroot(t^2-4t)
turning into (1-4/t), but wouldnt the 1 turn into 1/sqroot(x^2) which would equal 0? I know im wrong, just thinking out loud.
Also, you explained this better than my math teacher today, thanks for everything.