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Math Help - Integral of (x+3)/(x^2+4)

  1. #1
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    Oct 2009
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    Integral of (x+3)/(x^2+4)

    Integral of (x+3)/(x^2+4)

    I'm trying to do it by parts:

    u = x+3 du = 1
    dv = 1/(x^2+4) v = 1/2 arctan (x/2)

    but, I'm not sure this is the right way. It gets a bit messy and I assume I'm doing something wrong.
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  2. #2
    Senior Member
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    Dec 2008
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    We may use the fact that

    \frac{x+3}{x^2+4}=\frac{x}{x^2+4}+\frac{3}{x^2+4}.
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