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Math Help - tricky integral

  1. #1
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    Question tricky integral

    i am struggling with the integral:

    1/[sqrt(3)-2sin(x)] dx

    any help would be great

    thanks
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  2. #2
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    Quote Originally Posted by ben.mahoney@tesco.net View Post
    i am struggling with the integral:

    1/[sqrt(3)-2sin(x)] dx

    any help would be great

    thanks
    If you let x = 2 \tan^{-1} u, you integral becomes

    \frac{2\sqrt{3}}{(3u - \sqrt{3})(u - \sqrt{3})} = \frac{1}{u-\sqrt{3}} - \frac{3}{3u - \sqrt{3}}
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