i am struggling with the integral: 1/[sqrt(3)-2sin(x)] dx any help would be great thanks
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Originally Posted by ben.mahoney@tesco.net i am struggling with the integral: 1/[sqrt(3)-2sin(x)] dx any help would be great thanks If you let $\displaystyle x = 2 \tan^{-1} u$, you integral becomes $\displaystyle \frac{2\sqrt{3}}{(3u - \sqrt{3})(u - \sqrt{3})} = \frac{1}{u-\sqrt{3}} - \frac{3}{3u - \sqrt{3}}$
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