# Math Help - tricky integral

1. ## tricky integral

i am struggling with the integral:

1/[sqrt(3)-2sin(x)] dx

any help would be great

thanks

2. Originally Posted by ben.mahoney@tesco.net
i am struggling with the integral:

1/[sqrt(3)-2sin(x)] dx

any help would be great

thanks
If you let $x = 2 \tan^{-1} u$, you integral becomes

$\frac{2\sqrt{3}}{(3u - \sqrt{3})(u - \sqrt{3})} = \frac{1}{u-\sqrt{3}} - \frac{3}{3u - \sqrt{3}}$