To find the derivative of $\displaystyle f(x)=x^2-3x+21 $ at $\displaystyle x=4$, would you just find the derivative of $\displaystyle f(x)$, which is $\displaystyle 2x-3$, and plug in 4 for $\displaystyle x$, to get 5?
Thanks!
To find the derivative of $\displaystyle f(x)=x^2-3x+21 $ at $\displaystyle x=4$, would you just find the derivative of $\displaystyle f(x)$, which is $\displaystyle 2x-3$, and plug in 4 for $\displaystyle x$, to get 5?
Thanks!