Problem: Integrate (x^3 + 3x^2)/ (x+1) I'm missing something simple, I think - but I'm stuck. Thanks!
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Originally Posted by reflex Problem: Integrate (x^3 + 3x^2)/ (x+1) I'm missing something simple, I think - but I'm stuck. Thanks! start by doing the long division ... $\displaystyle \frac{x^3+3x^2}{x+1} = x^2 + 2x - 2 + \frac{2}{x+1}$ integrate the right side
With simple passages You obtain... $\displaystyle \frac{x^{3} +3x^{2}}{1+x} = x^{2}+2x-2+\frac{2}{1+x}$ ... so that... Kind regards $\displaystyle \chi$ $\displaystyle \sigma$
Cool, thanks...
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