f(x;y) = 1/ (9x^2 + y^2) what is the domain of this function? i know that 9x^2 + y^2 cannot be equals to 0 so where do i go from there?
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Originally Posted by yen yen f(x;y) = 1/ (9x^2 + y^2) what is the domain of this function? i know that 9x^2 + y^2 cannot be equals to 0 so where do i go from there? The domain is the set of all ordered pairs (x, y) where $\displaystyle x \in$ R\{0} and $\displaystyle y \in$ R\{0}.
hi $\displaystyle 9x^{2}+y^{2}$ cannot equal zero only when $\displaystyle x$ and $\displaystyle y$ aren't equal to zero.
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