Can someone teach me how to solce arccos(cos(7Pi/ 6))?
i tried to change 7pi/ 6 into the principal angle but what i thought of was:
cos (7pi/6)= -cos (pi/6)
although it is in the principal angle, i do not know how to continue after that.
but i thought that way that you did only applies to when the angle is in the principal range of 0 to 180 degrees?
so i was trying to convert 7pi/6 into the principal angle of cos x where x is in the principal range so that i can use the method that you have just used..