# Math Help - Double check

1. ## Double check

Umm for this question:

If f(x) = x^2(x-3) calculate the area between the X-axis, the lines x=4 and x=6 and the curve y=sqrt(f(x))

I keep on getting [12(sqrt(3)-1)]/5

BUT the txtbk answer is [12(4sqrt(3)-1)]/5

2. Originally Posted by xwrathbringerx
Umm for this question:

If f(x) = x^2(x-3) calculate the area between the X-axis, the lines x=4 and x=6 and the curve y=sqrt(f(x))

I keep on getting [12(sqrt(3)-1)]/5

BUT the txtbk answer is [12(4sqrt(3)-1)]/5

4. I'm trying to read through your work, but in the mean time can you tell me how you got the integral $A=\int_{4}^{6}x\sqrt{x-3}dx$?