f(x)= xe^(x)/(9x+b) How would you find the coordinates of f where the tangent lines are horizonal when b=-7?
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Originally Posted by ctran f(x)= xe^(x)/(9x+b) How would you find the coordinates of f where the tangent lines are horizonal when b=-7? If , then . Tangent lines are horizontal when the derivative is . So Now let and solve for . Since for any , we have . Now, substitute these values of back into .
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