i am having problems solving: integral of exp(x^2)*4x with respect to x i am using u = 4x and dv/dx = exp(x^2) but keep going round and round without getting a decent answer. where am i going wrong?
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Originally Posted by ben.mahoney@tesco.net i am having problems solving: integral of exp(x^2)*4x with respect to x i am using u = 4x and dv/dx = exp(x^2) but keep going round and round without getting a decent answer. where am i going wrong? use $\displaystyle u= x^2 \quad \Rightarrow du = 2x \cdot dx$
Last edited by ramiee2010; Oct 24th 2009 at 08:48 AM. Reason: latex editing
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