1. ## Extrema

1) The surface area of a cell in a honey comb is:

$S = 6hs + \frac{3s^2}{2}\left(\frac{\sqrt{3} - \cos(\theta)}{\sin(\theta)}\right)$

where h and s are positive constants and theta is the angle at which the upper faces meet the altitude of the cell. Find the angle theta ( $\pi/6 <= \theta <= \pi/2$) that minimizes the surface area S.

2. Originally Posted by seuzy13
1) The surface area of a cell in a honey comb is:

$S = 6hs + \frac{3s^2}{2}\left(\frac{\sqrt{3} - \cos(\theta)}{\sin(\theta)}\right)$

where h and s are positive constants and theta is the angle at which the upper faces meet the altitude of the cell. Find the angle theta ( $\pi/6 <= \theta <= \pi/2$) that minimizes the surface area S.
This has either a calculus like minimum in the interval $[\pi/6,\ \pi/2]$ or the minimum is at an end point of the interval.

So differentiate and set the derivative to zero and solve for a zero in the given interval, if there is no such root examine the value $S$ at each end of the interval.

CB