Find values of a and b so that the function has a local maximum

**Latszer** · October 22nd 2009, 09:18 PM

Find values of a and b so that the function has a local maximum at the point (12, 36).

f(x) = axe^(bx)

I really am just confused on how to do this.

Thanks in advance,

Tyler

**calum** · October 22nd 2009, 09:59 PM

First, derive the function:

$f'(x) = ae^{bx} + abxe^{bx} = e^{bx}(a + abx)$

Now, for stationary points, the derivative must equal 0.

So $0 = e^{bx}(a+ abx)$

Since $e^{bx}$ can never equal 0, we must have $(a + abx) = 0 \therefore x = \frac{-1}{b}$

For the stationary point to be at 12, we must have $12 = \frac{-1}{b} \therefore b = \frac{-1}{12}$

Going back to the original function, we must now have:

$36 = 12ae^{-1}$

$3 = \frac{a}{e} \therefore a = 3e$

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