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Math Help - integral

  1. #1
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    integral

    1/16-(x+1)^2

    here are my steps;
    1/16-x^2-2x-1

    1/-x^2-2x+15

    then use partial rule.
    (-x-5)(x-3)

    am i right?
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  2. #2
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    Quote Originally Posted by questionboy View Post
    1/16-(x+1)^2

    here are my steps;
    1/16-x^2-2x-1

    1/-x^2-2x+15

    then use partial rule.
    (-x-5)(x-3)

    am i right?
    16 - (x+1)^2 = [4 - (x+1)][4 + (x+1)] = (3-x)(5+x) = -(x-3)(x+5)
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  3. #3
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    Aren't they same?
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  4. #4
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    Quote Originally Posted by questionboy View Post
    Aren't they same?
    yes
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  5. #5
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  6. #6
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    Quote Originally Posted by questionboy View Post
    Replying with a Headbang is pointless.

    I suspect from skeeter's replies that he was hoping you would now proceed to get the required partial fraction decomposition. You've been taught how to do that, right?
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