The volume of a sphere is increasing at a rate of 10 cm3/sec. Find the rate of change of its surface area when its volume is 32π/3 cm3.
Using my crazy logic I ended up coming up with 20 / r... anything will help
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The volume of a sphere is increasing at a rate of 10 cm3/sec. Find the rate of change of its surface area when its volume is 32π/3 cm3.
Using my crazy logic I ended up coming up with 20 / r... anything will help
Find the radius r when the sphere has a volume of 32pi/3. Next, V = (4pi/3)*r^3, so V' = 4pi*r^2*r' = 10. Use this and the value you found for r to find r'. Also, A = 4pi*r^2, so A' = 8pi*r*r'. Use the values you found for r and r' to find A'.Quote:
Originally Posted by jawisbest
So did all of that and came up with 4.367... can anyone confirm this?
$\displaystyle \frac{dS}{dt} \ne 4.367$Quote:
Originally Posted by jawisbest
