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Math Help - Check real fast please =)

  1. #1
    Member mybrohshi5's Avatar
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    Check real fast please =)

    Find the derivative of the function.

    y=x*cos^(-1)(x) - sqrt(1-x^2)

    y'=cos^(-1)(x) + x(-1/sqrt(1-x^2)) + 2x/2(sqrt(1-x^2))

    y'= cos^(-1)(x)

    i think i did it right but it just seemed weird to me that it would reduce so much so i just wanted to make sure it is right haha

    thank you
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  2. #2
    Member Ruun's Avatar
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    Hi

    Could you make more specific wich is the argument of the \cos function?
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  3. #3
    MHF Contributor Amer's Avatar
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    Quote Originally Posted by mybrohshi5 View Post
    Find the derivative of the function.

    y=x*cos^(-1)(x) - sqrt(1-x^2)

    y'=cos^(-1)(x) + x(-1/sqrt(1-x^2)) + 2x/2(sqrt(1-x^2))

    y'= cos^(-1)(x)

    i think i did it right but it just seemed weird to me that it would reduce so much so i just wanted to make sure it is right haha

    thank you

    that's correct
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  4. #4
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    Quote Originally Posted by mybrohshi5 View Post
    Find the derivative of the function.

    y=x*cos^(-1)(x) - sqrt(1-x^2)

    y'=cos^(-1)(x) + x(-1/sqrt(1-x^2)) + 2x/2(sqrt(1-x^2))

    y'= cos^(-1)(x)

    i think i did it right but it just seemed weird to me that it would reduce so much so i just wanted to make sure it is right haha

    thank you
    It looks correct to me. When you add the last two terms together, they cancel.

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  5. #5
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    correct!

    Correct!
    Here is a useful site/program to help with checking derivative and integrals, and lots of other usefull stuff:
    - Wolfram|Alpha
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  6. #6
    Member mybrohshi5's Avatar
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    Quote Originally Posted by snaes View Post
    Correct!
    Here is a useful site/program to help with checking derivative and integrals, and lots of other usefull stuff:
    - Wolfram|Alpha
    Wow that site is amazing. i cant believe how fast and accurate it is. that thing is amazing lol. will definitely come in handy when i study for my exam on tuesday.

    thanks you so much again
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  7. #7
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    Glad you like it!
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