Find the surface area of the surface of revolution generated by revolving the graph , around the x-axis. This is what I got so far I don't know what to do next.
Last edited by superman69; October 21st 2009 at 11:00 PM. Reason: error
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Originally Posted by superman69 Find the surface area of the surface of revolution generated by revolving the graph , around the x-axis. This is what I got so far I don't know what to do next. I'm not sure how you got your result ... If y = f(x) then the surface area produced by revolution of the curve around the x-axis is: With your example you get: Use integration by substitution: Your integral becomes: Can you take it from here?
yes thank you
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