Find relative minima, relative maxima , abs minima, abs maxima
$\displaystyle f(x) = \frac{1}{3}x^3 + \frac{1}{2}x^2 - 2x$
At the interval $\displaystyle [-3,4]$
My problem is that i cant find critical points when i find the derivative of it
Howww?
Find relative minima, relative maxima , abs minima, abs maxima
$\displaystyle f(x) = \frac{1}{3}x^3 + \frac{1}{2}x^2 - 2x$
At the interval $\displaystyle [-3,4]$
My problem is that i cant find critical points when i find the derivative of it
Howww?
In this case the critical points is where the derivative is zero.
$\displaystyle f'(x)=x^2+x-2=0$
$\displaystyle (x+2)(x-1)=0$
$\displaystyle x=-2,1$
Thus, your fate is to check
$\displaystyle x=-3$ and $\displaystyle x=4$ (endpoints)
And,
$\displaystyle x=-2$ and $\displaystyle x=1$ (criticials)
And evaluate them at the function and see what gives the maximum and minimum values.