Results 1 to 2 of 2

Math Help - Easy Maxima minima problem

  1. #1
    Senior Member
    Joined
    Jul 2006
    From
    Shabu City
    Posts
    381

    Thumbs up Easy Maxima minima problem

    Find relative minima, relative maxima , abs minima, abs maxima
    f(x) = \frac{1}{3}x^3 + \frac{1}{2}x^2 - 2x
    At the interval [-3,4]
    My problem is that i cant find critical points when i find the derivative of it
    Howww?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Global Moderator

    Joined
    Nov 2005
    From
    New York City
    Posts
    10,616
    Thanks
    9
    Quote Originally Posted by ^_^Engineer_Adam^_^ View Post
    Find relative minima, relative maxima , abs minima, abs maxima
    f(x) = \frac{1}{3}x^3 + \frac{1}{2}x^2 - 2x
    At the interval [-3,4]
    My problem is that i cant find critical points when i find the derivative of it
    Howww?
    In this case the critical points is where the derivative is zero.
    f'(x)=x^2+x-2=0
    (x+2)(x-1)=0
    x=-2,1
    Thus, your fate is to check
    x=-3 and x=4 (endpoints)
    And,
    x=-2 and x=1 (criticials)
    And evaluate them at the function and see what gives the maximum and minimum values.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. maxima minima problem HELP!
    Posted in the Calculus Forum
    Replies: 8
    Last Post: November 11th 2010, 08:52 PM
  2. Applied Maxima and Minima Problem
    Posted in the Calculus Forum
    Replies: 3
    Last Post: April 14th 2010, 04:44 PM
  3. Maxima and minima trig problem
    Posted in the Calculus Forum
    Replies: 1
    Last Post: November 23rd 2009, 10:12 PM
  4. Maxima / Minima problem?
    Posted in the Calculus Forum
    Replies: 4
    Last Post: July 31st 2009, 06:27 AM
  5. Maxima/minima problem
    Posted in the Calculus Forum
    Replies: 2
    Last Post: January 20th 2006, 04:46 PM

Search Tags


/mathhelpforum @mathhelpforum