Hi I have a quick question about surface of revolution. I have the problem:

Find the area of the surface obtained by rotating the curve about thex-axis.

$\displaystyle x = 1 + 2y^2$

$\displaystyle 2<=y<=3$

I know the formula for $\displaystyle S = 2\pi y ds$

When I set up the integral can I use the bounds in the same way? I.e. from 2 to 3?