How do I find the equation of the tangent to the graph of f(x)=Sqrt x at the point x=9.
I know the gradient of the tangent which is 1/6.
But I have no idea how to do this.
Any help will be appreciated.
THANKS
How do I find the equation of the tangent to the graph of f(x)=Sqrt x at the point x=9.
I know the gradient of the tangent which is 1/6.
But I have no idea how to do this.
Any help will be appreciated.
THANKS
.. this is the equation of the curve .
so y=3
Last edited by mathaddict; Oct 21st 2009 at 08:01 AM.
How do I find the equation of the tangent to the graph of f(x)=Sqrt x at the point x=9.
I know the gradient of the tangent which is 1/6.
But I have no idea how to do this.
Any help will be appreciated.
THANKS
As you say, .
You now need
So the tangent is at the point .
Now use , the equation of the line with gradient through the point .