.The original equation is y=sqrtx/(x+4)
and the question asks to find the equation of tangent and normal line at point (9,3/13)
so I derived and found the tangent line to be y=-5/1020x + 243/884 and that is the correct answer, but I keep getting the normal line wrong
So for the normal line's slope I went -1/m and I got so the slope 1020/5 which is 204. and then I plugged it in to y-3/13=204(x-9)
and that gives y=204x-23865/13
I've redone it over and over again, but it still says the answer is wrong.
I'm just wondering where I went wrong.
Thank you for helping me!!!