Originally Posted by

**electricsparks** The original equation is y=sqrtx/(x+4)

and the question asks to find the equation of tangent and normal line at point (9,3/13)

so I derived and found the tangent line to be y=-5/1020x + 243/884 and that is the correct answer, but I keep getting the normal line wrong

So for the normal line's slope I went -1/m and I got so the slope 1020/5 which is 204. and then I plugged it in to y-3/13=204(x-9)

and that gives y=204x-23865/13

$\displaystyle \color{red}\mbox{I get here in the fraction }\,\frac{23868}{13}=1836$

Tonio

I've redone it over and over again, but it still says the answer is wrong.

I'm just wondering where I went wrong.

Thank you for helping me!!!