The horizontal tangent is given by findingI'm having trouble using the quotient rule of the derivative (i know how to do the power rule though). I'm not sure how I simplify in order to get the final answer/derivative. I need to use it in order to solve my question.
i need to determine the points at which the graph of the function
f(x)= (x^2)/(x-1) has a horizontal tangent.
what i think that i have to do is find the derivative of the function. then find the values of x by letting the derivative equal 0. then find the y values of the new x values by plugging them into the original equation. Am I right?