I need help in finding the maximum of this equation:
V(t)=2580+300cos(t*138.23007)
I found the derivative to be:
V'(t)=-41469.02100*sin(138.23007*t)
I just can't figure out how to find the maximum, please help. Thanks!
I need help in finding the maximum of this equation:
V(t)=2580+300cos(t*138.23007)
I found the derivative to be:
V'(t)=-41469.02100*sin(138.23007*t)
I just can't figure out how to find the maximum, please help. Thanks!
Well, this is ugly, but you have to equal the derivative to zero and find out when that happens:
$\displaystyle V'(t)=-41,469.021*\sin (138.23007t)=0 \Longrightarrow138.23007t=n\pi$, for some integer multiple of $\displaystyle \pi$ , so $\displaystyle t=\frac{n\pi}{138.23007}$
The value for n you'll get from, perhaps, other conditions on the problem.
Tonio