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Math Help - Need help in finding the maximum

  1. #1
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    Need help in finding the maximum

    I need help in finding the maximum of this equation:
    V(t)=2580+300cos(t*138.23007)

    I found the derivative to be:
    V'(t)=-41469.02100*sin(138.23007*t)

    I just can't figure out how to find the maximum, please help. Thanks!
    Last edited by Theressa; October 19th 2009 at 10:03 PM.
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  2. #2
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    Quote Originally Posted by Theressa View Post
    I need help in finding the maximum of this equation:
    V(t)=2580+300cos(w*138.23007)

    I found the derivative to be:
    V'(t)=-41469.02100*sin(138.23007*t)

    I just can't figure out how to find the maximum, please help. Thanks!

    As you can see, in the definition of V(t) there is no t in the right hand, so its derivative would be zero!
    I'm sure there's a typo somewhere but I can't say where.

    Tonio
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  3. #3
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    Quote Originally Posted by tonio View Post
    As you can see, in the definition of V(t) there is no t in the right hand, so its derivative would be zero!
    I'm sure there's a typo somewhere but I can't say where.

    Tonio
    Sorry about that, the w is supposed to be a t. My mistake.
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  4. #4
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    Quote Originally Posted by Theressa View Post
    I need help in finding the maximum of this equation:
    V(t)=2580+300cos(t*138.23007)

    I found the derivative to be:
    V'(t)=-41469.02100*sin(138.23007*t)

    I just can't figure out how to find the maximum, please help. Thanks!

    Well, this is ugly, but you have to equal the derivative to zero and find out when that happens:

    V'(t)=-41,469.021*\sin (138.23007t)=0 \Longrightarrow138.23007t=n\pi, for some integer multiple of \pi , so t=\frac{n\pi}{138.23007}

    The value for n you'll get from, perhaps, other conditions on the problem.

    Tonio
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