The acceleration of a particle moving along a straight line is given by a=10e^2t.
a.) Write an expression for the velocity v, in terms of time t, if v=5 when t=0
b.) During the time when the velocity increases from 5 to 15 how far does the particle travel?
c. Write an expression for the position s, in terms of time t, of the particle if s=0 when t=0
I don't even know how to start the problem if someone can please help me, and explain to me how you do the problem I would greatly appreciate it.
So because a=10e^2t the antiderivative of that would be:
so v= 5e^2t?? I'm kind of confused about this so I'm not sure of my answer.
and I have no clue how to do b and c; for B I was thinking of solving the v=5e^2t for t when v=15 so
15=2.5 which doesn't make any sense...