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Math Help - implicit differentiation problem

  1. #1
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    implicit differentiation problem



    0+6=cos(xy^2)(y^2 +2xyy')

    Wasn't sure how to isolate y', but I tried this:
    \frac{6}{cos(xy^2)}= (y^2) +(2xyy')

    \frac{6}{cos(xy^2)}- (y^2 )=(2xyy')

    Got a common denominator: cos(xy^2)and then divided by 2xy to get

    \frac{6-y^2cos(xy^2)}{(2xy)cos(xy^2)} =(y')
    Is this correct?
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  2. #2
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    Quote Originally Posted by hazecraze View Post


    0+6=cos(xy^2)(y^2 +2xyy')

    Wasn't sure how to isolate y', but I tried this:
    \frac{6}{cos(xy^2)}= (y^2) +(2xyy')

    \frac{6}{cos(xy^2)}- (y^2 )=(2xyy')

    Got a common denominator: cos(xy^2)and then divided by 2xy to get

    \frac{6-y^2cos(xy^2)}{(2xy)cos(xy^2)} =(y')
    Is this correct?
    yup

    looks perfect to me.
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