# Math Help - implicit differentiation problem

1. ## implicit differentiation problem

$0+6=cos(xy^2)(y^2 +2xyy')$

Wasn't sure how to isolate y', but I tried this:
$\frac{6}{cos(xy^2)}= (y^2) +(2xyy')$

$\frac{6}{cos(xy^2)}- (y^2 )=(2xyy')$

Got a common denominator: $cos(xy^2)$and then divided by 2xy to get

$\frac{6-y^2cos(xy^2)}{(2xy)cos(xy^2)} =(y')$
Is this correct?

2. Originally Posted by hazecraze

$0+6=cos(xy^2)(y^2 +2xyy')$

Wasn't sure how to isolate y', but I tried this:
$\frac{6}{cos(xy^2)}= (y^2) +(2xyy')$

$\frac{6}{cos(xy^2)}- (y^2 )=(2xyy')$

Got a common denominator: $cos(xy^2)$and then divided by 2xy to get

$\frac{6-y^2cos(xy^2)}{(2xy)cos(xy^2)} =(y')$
Is this correct?
yup

looks perfect to me.