implicit differentiation problem

**hazecraze** · October 19th 2009, 03:41 PM

$0+6=cos(xy^2)(y^2 +2xyy')$

Wasn't sure how to isolate y', but I tried this:
$\frac{6}{cos(xy^2)}= (y^2) +(2xyy')$

$\frac{6}{cos(xy^2)}- (y^2 )=(2xyy')$

Got a common denominator: $cos(xy^2)$ and then divided by 2xy to get

$\frac{6-y^2cos(xy^2)}{(2xy)cos(xy^2)} =(y')$
Is this correct?

**adkinsjr** · October 19th 2009, 03:57 PM

Originally Posted by hazecraze

$0+6=cos(xy^2)(y^2 +2xyy')$

Wasn't sure how to isolate y', but I tried this:
$\frac{6}{cos(xy^2)}= (y^2) +(2xyy')$

$\frac{6}{cos(xy^2)}- (y^2 )=(2xyy')$

Got a common denominator: $cos(xy^2)$ and then divided by 2xy to get

$\frac{6-y^2cos(xy^2)}{(2xy)cos(xy^2)} =(y')$
Is this correct?

yup

looks perfect to me.

Thread: implicit differentiation problem

LinkBack

Thread Tools

Display

implicit differentiation problem

Similar Math Help Forum Discussions

Implicit differentiation problem (I think?)

implicit differentiation problem

Implicit Differentiation Problem

Implicit Differentiation Problem

Implicit Differentiation Problem

Search Tags