Find the derivative of the function. $\displaystyle y=e^(2xsinx)$ [e raised to 2xsin(x)]
$\displaystyle e^u=e^udu$
$\displaystyle y=e^(2xsinx)du$
product rule
$\displaystyle e^(2xsin(x))[(2sinx+2xcosx)]$
Where did I falter?
Find the derivative of the function. $\displaystyle y=e^(2xsinx)$ [e raised to 2xsin(x)]
$\displaystyle e^u=e^udu$
$\displaystyle y=e^(2xsinx)du$
product rule
$\displaystyle e^(2xsin(x))[(2sinx+2xcosx)]$
Where did I falter?