Find the derivative of the function.$\displaystyle y=e^(2xsinx)$ [e raised to 2xsin(x)]

$\displaystyle e^u=e^udu$

$\displaystyle y=e^(2xsinx)du$

product rule

$\displaystyle e^(2xsin(x))[(2sinx+2xcosx)]$

Where did I falter?

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- Oct 19th 2009, 11:20 AMhazecrazederivative with an e function
**Find the derivative of the function.**$\displaystyle y=e^(2xsinx)$ [e raised to 2xsin(x)]

$\displaystyle e^u=e^udu$

$\displaystyle y=e^(2xsinx)du$

product rule

$\displaystyle e^(2xsin(x))[(2sinx+2xcosx)]$

Where did I falter? - Oct 19th 2009, 11:37 AMadkinsjr
- Oct 19th 2009, 12:23 PMtonio
- Oct 19th 2009, 01:46 PMhazecraze
- Oct 19th 2009, 02:52 PMtom@ballooncalculus
Probably it needs sin(x) not sinx

- Oct 19th 2009, 02:58 PMhazecraze
This is how it looked when I submitted it:

y'=http://www.webassign.net/cgi-bin/pal...E%3C%2Fmath%3E - Oct 19th 2009, 07:27 PMtonio