Water is flowing at the rate of 50 m^3/min from a conical reservoir (vertex down) of base radius of 45 m and height of 6 m.
How fast is the water level falling when the water is 5 m deep?
help please?
Let V(t) = the volume of water in the cone at time t. Then dV/dt = -50. Given that the height and base radius of the water cone remain proportional as water pours out of the reservoir, find an equation for the water level in terms of the volume of water remaining at time t. Differentiate both sides and plug in h = 5 and V' = -50.