Thread: integration by parts

HI

calculating integral sign ("S") b=2; a=0 (e^-x/(1-e^-2)) dx

So if u = x then du = dx

then I need a dv .... if dv = e^-1 then v = e^-1 doesn't it? and how does this help me if I now introduce V?

how can I get all of these "e"s into "u"s?

Thanks

Calculus Beginner

Originally Posted by calcbeg

HI

calculating integral sign ("S") b=2; a=0 (e^-x/(1-e^-2)) dx

So if u = x then du = dx

then I need a dv .... if dv = e^-1 then v = e^-1 doesn't it? and how does this help me if I now introduce V?

how can I get all of these "e"s into "u"s?

Thanks

Calculus Beginner

did you mean ...



or what you posted?

what I posted - there is an x then the e stuff

Originally Posted by calcbeg

what I posted - there is an x then the e stuff

your notation is a bit confusing ...

("S") b=2; a=0 (e^-x/(1-e^-2)) dx

is the integrand



or is it

If it really is, as you said, ("S") b=2; a=0 (e^-x/(1-e^-2)) dx
which is , then that is the same as and that should be easy to integrate.

Originally Posted by HallsofIvy

If it really is, as you said, ("S") b=2; a=0 (e^-x/(1-e^-2)) dx
which is , then that is the same as and that should be easy to integrate.

Why did you take out ? Wouldn't the e be to the negative 2 power-- since all of it is a constant?