# Math Help - tangent to a curve

1. ## tangent to a curve

Find the tangent line to $y^3+y^2-5y-x^2+4=0$ at the point(1,1)

2. Originally Posted by wantanswers
Find the tangent line to $y^3+y^2-5y-x^2+4=0$ at the point(1,1)
use implicit differentiation to find $\frac{dy}{dx}$ , then sub in x = 1 and y = 1 into the result to get the slope at the point (1,1).

use the point-slope form to get the tangent line equation.

3. The gradients goes to infinity

4. Originally Posted by wantanswers
The gradients goes to infinity
that tells you something about the tangent line then, doesn't it?