# Thread: tangent to a curve

1. ## tangent to a curve

Find the tangent line to $y^3+y^2-5y-x^2+4=0$ at the point(1,1)

Find the tangent line to $y^3+y^2-5y-x^2+4=0$ at the point(1,1)
use implicit differentiation to find $\frac{dy}{dx}$ , then sub in x = 1 and y = 1 into the result to get the slope at the point (1,1).

use the point-slope form to get the tangent line equation.

3. The gradients goes to infinity