Find the tangent line to $\displaystyle y^3+y^2-5y-x^2+4=0$ at the point(1,1)
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Originally Posted by wantanswers Find the tangent line to $\displaystyle y^3+y^2-5y-x^2+4=0$ at the point(1,1) use implicit differentiation to find $\displaystyle \frac{dy}{dx}$ , then sub in x = 1 and y = 1 into the result to get the slope at the point (1,1). use the point-slope form to get the tangent line equation.
The gradients goes to infinity
Originally Posted by wantanswers The gradients goes to infinity that tells you something about the tangent line then, doesn't it?
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