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Math Help - tangent to a curve

  1. #1
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    tangent to a curve

    Find the tangent line to y^3+y^2-5y-x^2+4=0 at the point(1,1)
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  2. #2
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    Quote Originally Posted by wantanswers View Post
    Find the tangent line to y^3+y^2-5y-x^2+4=0 at the point(1,1)
    use implicit differentiation to find \frac{dy}{dx} , then sub in x = 1 and y = 1 into the result to get the slope at the point (1,1).

    use the point-slope form to get the tangent line equation.
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    The gradients goes to infinity
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  4. #4
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    Quote Originally Posted by wantanswers View Post
    The gradients goes to infinity
    that tells you something about the tangent line then, doesn't it?
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